Meganotegniek N5 — Document

November 2020 — N5 — Meganotegniek

N5 2020 Nated Engineering

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🎯 100 marks ⏱️ 3h 📄 6 pages 📝 32 items found

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Q1— Section header —

1.1Bepaal die spoed van rat E indien arm E stilstaan. (8\

1.2Bepaal die spoed van arm E indien rat A vas is. (4\ [12]12

Q2— Section header —

2.1Noem VIER funksies van 'n reduksieratkas. (4\

2.2FIGUUR 2 hier onder toon 'n reduksieratkas met 'n tweevoudige wurm, 'n wurmrat en vier ratte. Die wurm as is aan 'n elektriese motor gekoppel wat teen 1 200 r/min dr aai. A=120 tande B=30 tande C=38 tande

2.2.1Die spoed van die wurmrat. (5\

2.2.2Die leweringspoed van die ratkas. (3\

2.2.3Die snelheidsverhouding van die ratkas. (3\ [15]15

Q3— Section header —

3.1Vervoerders is met terug keer toestelle ('holdback devices'\toegerus. Noem DRIE algemene tipes terug keer toestelle wat vervoerders verhoed om agteruit te loop. (3\

3.2

3.2.1Die effektiewe trekspanning tussen die katrolle. (3\

3.2.2Die spanning aan die slap kant (T \ die spankant (T (6\

3.2.3Die las op die laers van die band. (3\

3.2.4Die krag van die motor indien die rendement van die aandrywing 80% is. (3\ [18] Wurm A=26 tande B=46 tande C=22 tande18

Q4— Section header —

Q5— Section header —

5.1'n Lokomotief sleep 'n wa teen 75 km/h terwyl 'n konstante trekkrag van 850 N op die trekstang uitgeoefen word. Ignoreer die rolweerstand tussen die wiele en die spore. Bereken die volgende:

5.1.1Die arbeid wat in 15 minute verrig word. (4\

5.1.2Die krag wat vereis word. (2\

5.2'n Elektriese lokomotief met 'n totale massa van 260 ton versnel teen 0,06 m/s teen 'n helling van 1 tot 120. Die rolweerstand is 0,8% van die massa van die trein. Bereken die volgende:

5.2.1Die trekkrag om die wrywingsweerstand te oorkom. (2\

5.2.2Die trekkrag om gravitasie te oorkom. (2\

5.2.3Die trekkrag om die trein te versnel. (2\

5.2.4Die krag wat teen 'n spoed van 72 km/h nodig is. (4\

5.2.5Die kinetiese energie van die lokomotief teen 72 km/h. (2\ [18] 819022518

Q6— Section header —

6.1Noem TWEE hoofverskille tussen die konstruksies van 'n goederehyser en 'n passasierhyser (4\

6.2Die belaste kou van 'n goederehyser het 'n massa van 1 500 kg. Die kabel loop oor 'n drom aan die bokant van die skag na 'n teenwig van 600 kg. Die kou en die teenwigmassa beweeg tussen gidse en die wrywingskrag by elke

6.2.1Die motorkrag wat nodig is om die maksimum versnelling aan te dryf. (8\

6.2.2Die kabelspanning tydens spoedvermindering indien die maksimum snelheid 5 m/s is en spoedvermindering oor die laaste 4 m van beweging teen 'n eenvormige tempo van maksimum snelheid tot stilstand plaasvind.

Mark Allocation

Total100 marks

Sections12 + 15 + 18 + 19 + 18 + 18 = 100 marks

Paper information

TitleDocument

SubjectMeganotegniek

LevelN5

Document typeQuestion paper

Year2020

MonthNovember

Pages9

Downloads4

Examination context

Decade2020s

Years ago6y

SeasonSpring (SH)

Start daySunday

Exam periodNovember 2020

Days since exam2,169

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How to use this resource for revision

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For stronger examination practice, complete the paper without unnecessary interruptions and keep track of the questions that take the most time. Afterwards, review the memorandum and separate knowledge gaps from mistakes caused by interpretation, calculation, structure, or examination technique.

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