Fitting And Mechining Theory N2 — Document

November 2023 — N2 — Fitting And Mechining Theory

N2 2023 Nated Engineering

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🎯 100 marks ⏱️ 3h 📄 9 pages 📝 74 items found

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Q1— Section header —

1.1State FIVE characteristics of effective machine guards (5\ OR

1.2State FIVE regulations associated with first aid certification for underground and surface mine workers, according to the Minerals Act No. 50 of 1991. (5\ [5]5

Q2— Section header —

2.1Name THREE types of coupling misalignment. (3\

2.2FIGURE 1 shows the diagram of a coupling. FIGURE 1

2.2.1Name the coupling shown in FIGURE 1. (1\

2.2.2Which group does this coupling belong to? (1\

2.2.3Name the part labelled A. (1\ [6] 110220326

Q3— Section header —

3.1Name three classes of fits. (3\ 3. Explain the following terms relating to limits and fits 3.

2.47

Q4— Section header —

4.1Name the THREE types of loads that bearings support (3\

4.2Name TWO reasons why plain bearings fail. (2\ [5]5

Q5— Section header —

5.1Lubricants are classified as solid, semi solid and liquid types. State the classification of the lubricant used in each of the following lubricators:

5.1.1Splash feed lubricator

5.1.2Stauffer grease cup lubricator

5.1.3

5.2Indicate whether the following statements are TRUE or FALSE by writing 5,2,3\n the ANSWER BOOK.

5.2.1A check valve prevents liquids from flowing backwards.

5.2.2Pressure relief valves stay open all the time to allow fluid to return to the tank, thus preventing damage to the system.

5.2.36

Q6— Section header —

6.1Indicate whether the following statements are TRUE or FALSE by writing

6.1.5in the ANSWER BOOK.

6.1.1The disadvantage of a luminium is that it rusts very easily.

6.1.2A seal helps to maintain the pressure in a container

6.1.3Teflon is the cheapest packing material available

6.1.4Graphite is a form of carbon and may be used as a seal material

6.1.5

6.2Name FOUR methods of joining steel water pipes (4\ [9]9

Q7— Section header —

7.1State TWO functions of a pump. (2\

7.2State the difference between piston pumps and plunger pumps (2\

7.3pump (2\ [6] 110220326

Q9— Section header —

9.1State the causes of the following V belt problems:

9.1.1Small cracks

9.1.2Swelling

9.1.3

9.2Name the TWO gear profiles in relation to gear drives. (2\

9.3Name FOUR types of chains used in the industry. (4\

9.4State TWO purposes of reduction gearboxes. (2\ [11] TOTAL SECTION A: 6011

Q10— Section header —

10.1Name the components associated with the ISO symbols shown in FIGURE 3 below. Write only the answer next to the letter (A D\ in the ANSWER BOOK. (4\ FIGURE 3

10.2State FIVE main advantages of a pneumatic system (5\

10.3State the function of each of the following hydraulic or pneumatic components:

10.3.1Pressure relief valve

10.3.2Reservoir

10.3.3Hydraulic pump

10.3.4Water rap

10.3.5

10.4Name THREE types of valves you would find in a typical hydraulic system. (3\

10.5State any THREE tasks that must be carried out during the daily maintenance on pneumatic systems. (3\ [20] 1102203220

Q11— Section header —

11.1State the function of a lathe mandrel. (1\

11.2State FOUR advantages of using mandrels on a lathe. (4\

11.3One method used to set over the tailstock when taper turning on the centre lathe is the graduated sleeve method.

11.3.1State TWO advantages of using this method.

11.3.2

Q12— Section header —

12.1State TWO functions of the dividing head (2\

12.2Name the milling cutters shown in FIGURE 5 by writing only the answer next to the letter (A C\ in the ANSWER BOOK. FIGURE 5 (3\

12.3A milling machine has to mill 18 teeth on a gear blank. Calculate the required indexing using a Cincinnati dividing head. THE CINCINNATI DIVIDING HEAD Side 1 24 25 28 30

12.4Calculate the feed in mm/min of an 85 mm diameter cutter with 15 teeth and a feed of 0.08 per tooth. The cutting speed of the material is 30 m/min. (5\

12.5State the reason for surface grinding. (1\

12.6State ONE difference between off hand grinding and precision grinding

12.7Name TWO types of grinding wheels (2\ [20] TOTAL SECTION B: 40 GRAND TOTAL: 100 1102203220

Mark Allocation

Total100 marks

Sections5 + 6 + 7 + 5 + 6 + 9 + 6 + 5 + 11 + 20 + 20 + 20 = 120 marks

Paper information

TitleDocument

SubjectFitting And Mechining Theory

LevelN2

Document typeQuestion paper

Year2023

MonthNovember

Pages10

Downloads2

Examination context

Decade2020s

Years ago3y

SeasonSpring (SH)

Start dayWednesday

Exam periodNovember 2023

Days since exam1,074

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